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 如何基于Excel中的列标题选择列？

假设您有一个包含多个列的大型工作表，现在，您想根据列标题名称选择特定的列。 要在大型工作表中逐列查找会浪费很多时间，本文将介绍一种快速的方法来解决Excel中的这一问题。

根据列标题名称和VBA代码选择一个列

根据列标题名称和VBA代码选择一个列

以下VBA代码可以帮助您根据特定的标题名称选择列，请按以下步骤操作：

1。 按住 ALT + F11 键打开 Microsoft Visual Basic应用程序 窗口。

2。 点击 插页 > 模块，然后将以下代码粘贴到 模块 窗口。

VBA代码：根据列标题名称选择列：

Sub FindAddressColumn()
'Updateby Extendoffcie
    Dim xRg As Range
    Dim xRgUni As Range
    Dim xFirstAddress As String
    Dim xStr As String
    On Error Resume Next
    xStr = "Name"
    Set xRg = Range("A1:P1").Find(xStr, , xlValues, xlWhole, , , True)
    If Not xRg Is Nothing Then
        xFirstAddress = xRg.Address
        Do
            Set xRg = Range("A1:P1").FindNext(xRg)
            If xRgUni Is Nothing Then
                Set xRgUni = xRg
            Else
                Set xRgUni = Application.Union(xRgUni, xRg)
            End If
        Loop While (Not xRg Is Nothing) And (xRg.Address <> xFirstAddress)
    End If
    xRgUni.EntireColumn.Select
End Sub

备注：在上面的代码中， A1：P1 是您要从中选择列的标题范围，并且“名字”中的“ xStr =“名称” 是要基于其选择列的标题名称。 请根据需要更改它们。

3。 复制并粘贴代码后，请按 F5 键以运行此代码，并且具有特定标题名称的所有列均已被选中，请参见屏幕截图：

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Comments (8)
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Matthew Reynolds
Matthew Reynolds
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Good job, works great!
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Justo Torres
Justo Torres
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Hi everyone...

How can I make it so that only the column data is selected, without the header, instead of the entire column?

Thanks
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sizwe
sizwe
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Thank you spo much saved my day !
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Jay
Jay
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Thanks - at first it seemed to work, but then I noticed it didn't include the first-found column - it started with the second and on.

Which is explainable: you set xRg twice, but you do not include the first one.

TBH: initially I thought it worked fine, but then that 'error' showed up and I had to figure out why....

I fixed it as follows: (in Excel the comments will turn green and show my edits: '***)

<code>

Sub FindAddressColumn()

'Updateby Extendoffcie

Dim xRg As Range

Dim xRgUni As Range

Dim xFirstAddress As String

Dim xStr As String

On Error Resume Next
xStr = "Name"
Set xRg = Range("A1:P1").Find(xStr, , xlValues, xlPart, , , True)

If Not xRg Is Nothing Then

xFirstAddress = xRg.Address

Do

If xRgUni Is Nothing Then

Set xRgUni = Range(xFirstAddress) '*** Using the first-found range

Else

Set xRgUni = Application.Union(xRgUni, xRg)

End If



Set xRg = Range("A1:P1").FindNext(xRg) '*** Now searching for the second/next ones



Loop While (Not xRg Is Nothing) And (xRg.Address <> xFirstAddress)

End If

xRgUni.EntireColumn.Select

End Sub


</code>

This now works for me, but I hope to learn from you if I overlooked anything.
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Deep
Deep     Jay
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Hi, Can you suggest the macro for the issue mentioned below by Shaun
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Lourdu
Lourdu
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Hi, looks great work. But I am getting the compile error: Argument not optional while highlighting the ". Union". What should I do?
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Shaun
Shaun
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This is great, but what if I wanted to copy say, CustomerName, OrderNumber, OrderDate, FulfillmentDate, OrderStatus from Sheet1 with many more columns.
How do I only specify the columns that are needed to be copied to another sheet? This seems to only specify one column.
I have tried some things, but the problem is more where the columns are not necesarily in the same order on the source sheet. The source data in Sheet1 is pasted from the Windows clipboard to the Excel sheet.

It may be, CustomerName, OrderDate, OrderNumber, OrderStatusm FulfillmentDate or some other order.

I need them to be copied into a new sheet in a specific order as there are formulas in Sheet2 that are applied to what is copied from Sheet1 to Sheet2.

Other than shifting columns around after pasting from Windows clipboard, I can't figure this out.

Please help if possible.

Thank you kindly for the above though.
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George
George     Shaun
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Dim xRg As Range
Dim xRgUni As Range
Dim xFirstAddress As String
Dim xStr As String

Are variables being declared.

Hence to use the above code again for another column you would have to declare new variables.

Dim xRg2 As Range
Dim xRgUni2 As Range
Dim xFirstAddress2 As String
Dim xStr2 As String

And replace every instance of xRg with xRg2 in the code ect. Does that make sense?
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