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如何在Excel中快速将日期转换为单词?

通常,我们通常在Excel中将日期转换为其他日期格式或数字,但是您是否遇到过将日期转换为英语单词的问题,如下图所示? 实际上,没有内置功能可以处理它,而是VBA代码。
doc日期到单词1

使用定义的函数将日期转换为单词


使用定义的函数将日期转换为单词

这是一个宏代码,可以帮助您将日期转换为单词。

1.启用您使用的工作表,然后按 Alt + F11键 打开钥匙 Microsoft Visual Basic应用程序 窗口。

2。 点击 插页 > 模块 并将以下代码粘贴到脚本中。

VBA:将日期转换为单词

Function DateToWords(ByVal xRgVal As Date) As String
' Update by Extendoffice on 20240926
    Dim xYear As String
    Dim Hundreds As String
    Dim Decades As String
    Dim xTensArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    
    ' Initialize arrays
    xOrdArr = Array("First", "Second", "Third", "Fourth", "Fifth", "Sixth", _
                    "Seventh", "Eighth", "Ninth", "Tenth", "Eleventh", "Twelfth", _
                    "Thirteenth", "Fourteenth", "Fifteenth", "Sixteenth", _
                    "Seventeenth", "Eighteenth", "Nineteenth", "Twentieth", _
                    "Twenty-first", "Twenty-second", "Twenty-third", "Twenty-fourth", _
                    "Twenty-fifth", "Twenty-sixth", "Twenty-seventh", "Twenty-eighth", _
                    "Twenty-ninth", "Thirtieth", "Thirty-first")
    
    xCardArr = Array("", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", _
                    "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", _
                    "Seventeen", "Eighteen", "Nineteen")
    
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety")
    
    ' Extract year
    xYear = CStr(Year(xRgVal))
    Decades = Mid$(xYear, 3)
    
    ' Handle decades
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & xCardArr(CInt(Right$(Decades, 1)))
    End If
    
    ' Handle hundreds
    Hundreds = Mid$(xYear, 2, 1)
    If CInt(Hundreds) Then
        Hundreds = xCardArr(CInt(Hundreds)) & " Hundred "
    Else
        Hundreds = ""
    End If
    
    ' Construct English representation of the date
    DateToWords = xOrdArr(Day(xRgVal) - 1) & " " & Format$(xRgVal, "mmmm") & " " & _
                  xCardArr(CInt(Left$(xYear, 1))) & " Thousand " & Hundreds & Decades
End Function


doc日期到单词2

3.保存代码并返回到工作表,选择一个要在其中输出结果的单元格,键入此公式 = DateToWords(A2) (A2是您使用的日期),按 输入 键,然后将自动填充手柄拖到所需的单元格上。 看截图:
doc日期到单词3doc日期到单词4


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Comments (25)
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This comment was minimized by the moderator on the site
The spelling of 9th is wrong. It's written Nineth, but it should be Ninth.
This comment was minimized by the moderator on the site
Thank you for your message. I have corrected and updated the code accordingly. Thank you.
This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST TWENTY HUNDRED NINETY-EIGHT
In this vba have error
convert it1998 but it shows TWENTY HUNDRED NINETY-EIGHT
This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST NINETEEN HUNDRED NINETY EIGHT
I need dob into words in upper format but i use this micros in excel i got this
07/08/1998 SEVENTH AUGUST ONE THOUSAND NINE HUNDRED NINETY-EIGHT which is not usefull
This comment was minimized by the moderator on the site
Hi, MAX, I have modified the VBA, please try and let me know if it works. Thanks.
Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Decades As String
    Dim years As String
    Dim xTensArr As Variant
    Dim xyearArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    
    
      xyearArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")

    years = xyearArr(CInt(Year(xRgVal) / 100)) & " Hundred"
    
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If

    DateToWords = UCase(xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  years & " " & Decades)
End Function

This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST TWENTY HUNDRED NINETY-EIGHT
In this vba have error
convert it1998 but it shows TWENTY HUNDRED NINETY-EIGHT
This comment was minimized by the moderator on the site
Hi, try this vba:
Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Decades As String
    Dim years As String
    Dim xTensArr As Variant
    Dim xyearArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    
    
      xyearArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")

    years = xyearArr(Fix(Year(xRgVal) / 100)) & " Hundred"
    
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If

    DateToWords = UCase(xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  years & " " & Decades)
End Function

This comment was minimized by the moderator on the site
آپ کا بہت شکریہ
This comment was minimized by the moderator on the site
It is giving the #NAME? Error
This comment was minimized by the moderator on the site
I would like to add text to the output, for instance, 1958 gets converted to One Thousand Nineteen Hundred Fifty Eight and I would like it to say One Thousand Nineteen Hundred and Fifty Eight. Can someone give me an example of how I can do this please?
This comment was minimized by the moderator on the site
thank u for helping me . very useful in converting date of birth in word
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Sir/Madam

It is very useful for me.

Really Amazing and helped to solve the problem within a minute.

Thank you for uploading this document. Very nice
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how to use this code in vb6 for a textbox
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date to word in gujarati language avilable ? please answer me. 9427909038
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I think it does not work for other languages except english.
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