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如何在Excel中vlookup并返回没有重复的多个值? 

有时,您可能需要vlookup并将多个匹配的值一次返回到单个单元格中。 但是,如果在返回的单元格中填充了一些重复的值,那么在返回所有匹配值时如何忽略重复项,而仅保留唯一值,如下面的Excel截图所示?

doc返回多个唯一值1

Vlookup并使用用户定义的函数返回多个没有重复的匹配值


Vlookup并使用用户定义的函数返回多个没有重复的匹配值

以下VBA代码可以帮助您返回多个不重复的匹配值,请这样做:

1。 按住 Alt + F11键 键打开 Microsoft Visual Basic应用程序 窗口。

2。 点击 插页 > 模块,然后将以下代码粘贴到 模块 窗口。

VBA代码:Vlookup并返回多个唯一的匹配值:

Function MultipleLookupNoRept(Lookupvalue As String, LookupRange As Range, ColumnNumber As Integer)
    Dim xDic As New Dictionary
    Dim xRows As Long
    Dim xStr As String
    Dim i As Long
    On Error Resume Next
    xRows = LookupRange.Rows.Count
    For i = 1 To xRows
        If LookupRange.Columns(1).Cells(i).Value = Lookupvalue Then
            xDic.Add LookupRange.Columns(ColumnNumber).Cells(i).Value, ""
        End If
    Next
    xStr = ""
    MultipleLookupNoRept = xStr
    If xDic.Count > 0 Then
        For i = 0 To xDic.Count - 1
            xStr = xStr & xDic.Keys(i) & ","
        Next
        MultipleLookupNoRept = Left(xStr, Len(xStr) - 1)
    End If
End Function

3。 插入代码后,然后单击 工具 > 參考資料 在打开 Microsoft Visual Basic应用程序 窗口,然后在弹出 参考– VBAProject 对话框,检查 Microsoft脚本运行时 在选项 可用参考 列表框,请参见屏幕截图:

doc返回多个唯一值2

4。 然后点击 OK 关闭对话框,保存并关闭代码窗口,返回到工作表,然后输入以下公式: =MultipleLookupNoRept(E2,A2:C17,3) 放入要输出结果的空白单元格中,按 输入 获得所需正确结果的关键。 看截图:

doc返回多个唯一值3

备注:在以上公式中, E2 是您要查询的条件, A2:C17 是您要使用的数据范围,数字 3 是包含返回值的列号。


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  • To post as a guest, your comment is unpublished.
    Drew · 1 years ago
    This is great! How would I adapt this to not add null values to the dictionary? I've tried adding the bold below, but the final string is still returning with ,"", instances.


    xRows = LookupRange.Rows.Count
    For i = 1 To xRows
    If LookupRange.Columns(1).Cells(i).Value = Lookupvalue And Not IsEmpty(LookupRange.Columns(1).Cells(i).Value) Then
    xDic.Add LookupRange.Columns(ColumnNumber).Cells(i).Value, ""
    End If
    Next

    Thanks,
  • To post as a guest, your comment is unpublished.
    Jame · 1 years ago
    Hello , I did as u told and it great but it still havent solve one of my problem , what happen when u unique value in each month ? =MultipleLookupNoRept(E2,A2:C17,3) , i try to E2&1 for January but it not working
    • To post as a guest, your comment is unpublished.
      skyyang · 1 years ago
      Hi, Jame,
      Could you give your problem as a screenshot here, so that i can understand your requires?
  • To post as a guest, your comment is unpublished.
    srikanth · 2 years ago
    hi,
    while the time of lot value multivlooks my worksheet got hang.is there any other ways to multivlookupwithoutrepeation????

    and also i used on new desktop also its getting hang only...

    my data value is around 10,000 rows
  • To post as a guest, your comment is unpublished.
    rasike001 · 2 years ago
    Hi

    I wanted to create a list in a table from this instead of all results in one cell. So I have used a formula similar below (what you have suggested)

    =LOOKUP(2, 1/((COUNTIF($E$1:E1, $B$2:$B$12)=0)*($D$2=$A$2:$A$12)), $B$2:$B$12)

    However, this is taking a long time to process from a large set of data.
    Is there any alternative method to process this faster?
    Thanks again
    Rasike
  • To post as a guest, your comment is unpublished.
    Imre · 2 years ago
    xStr = xStr & xDic.Keys(I) & "," to be this: xStr = xStr & xDic.Keys(I) & ", "

    Is there a way to replace "," with in-cell ALT+ENTER, so that the results will be in the same cell but on different lines? Do I need to introduce additional VBA module for that and combine them?

    Also, this code is quite slow when looping over huge tables. Anyone knows any faster solutions?
    • To post as a guest, your comment is unpublished.
      skyyang · 2 years ago
      Hi, Imre,
      To separate the result values by Alt + Enter keys, please apply the following User Defined Function:

      Function MultipleLookupNoRept(Lookupvalue As String, LookupRange As Range, ColumnNumber As Integer)
      Dim xDic As New Dictionary
      Dim xRows As Long
      Dim xStr As String
      Dim i As Long
      On Error Resume Next
      xRows = LookupRange.Rows.Count
      For i = 1 To xRows
      If LookupRange.Columns(1).Cells(i).Value = Lookupvalue Then
      xDic.Add LookupRange.Columns(ColumnNumber).Cells(i).Value, ""
      End If
      Next
      xStr = ""
      MultipleLookupNoRept = xStr
      If xDic.Count > 0 Then
      For i = 0 To xDic.Count - 1
      xStr = xStr & xDic.Keys(i) & Chr(10) + Chr(13)
      Next
      MultipleLookupNoRept = Left(xStr, Len(xStr) - 1)
      End If
      Debug.Print xStr
      End Function

      And then do with the above steps in this article, at last, after entering the formula, you should click Wrap Text under the Home tab.
  • To post as a guest, your comment is unpublished.
    Demetre · 3 years ago
    Is there a way to add a space in between the multiple values retrieved in the results without introducing a comma at the end of the list? For example your result above would show as: "Emily, James, Daisy, Gary" instead of like this: "Emily,James,Daisy,Gary"

    I tried to edit this portion of the VBA code: xStr = xStr & xDic.Keys(I) & "," to be this: xStr = xStr & xDic.Keys(I) & ", "

    That did add the space in between the values, but it also added a comma after the last value. "Emily, James, Daisy, Gary,"

    Is there a way to make it work with the space but without the extra comma after the last value?
    • To post as a guest, your comment is unpublished.
      skyyang · 2 years ago
      Hello, Demetre,
      Use the space to separate the values, you just need to change the vba code:
      from xStr = xStr & xDic.Keys(i) & "," to be this: xStr = xStr & xDic.Keys(i) & " "

      Please try it.
  • To post as a guest, your comment is unpublished.
    Tom · 3 years ago
    what if I wanted to create a list in a table from this instead of all results in one cell?
    • To post as a guest, your comment is unpublished.
      skyyang · 3 years ago
      Hello, Tom,
      If you want to extract the unique values in a list of cells instead of one cell, the following formula may help you:

      =LOOKUP(2, 1/((COUNTIF($E$1:E1, $B$2:$B$12)=0)*($D$2=$A$2:$A$12)), $B$2:$B$12)

      Please try it.
      • To post as a guest, your comment is unpublished.
        clifford · 1 months ago
        Hi skyyang what if you want the result as a column?
      • To post as a guest, your comment is unpublished.
        rasike001 · 2 years ago
        Hi Skyyang,

        Thank you very much for this formula.
        This works for me. However, it is taking a long time to process from a large set of data.
        Can we modify this formula to work this bit faster?
        Thanks again
        Rasike