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如何在Excel中检查数字是否为素数?

众所周知,素数是一个自然数,仅包含两个不同的自然数除数:一个和它本身。 如果您在工作表中有数字列表,那么如何检查数字是否为质数?

使用数组公式检查数字是否为质数

使用用户定义的功能检查数字是否为质数


箭头蓝色右气泡 使用数组公式检查数字是否为质数

以下公式可以帮助您确定数字是否是质数,请按照以下步骤操作:

1。 在数据旁边的空白单元格(例如C2)中输入以下公式:

=IF(A2=2,"Prime",IF(AND(MOD(A2,ROW(INDIRECT("2:"&ROUNDUP(SQRT(A2),0))))<>0),"Prime","Not Prime")) (A2 是该单元格包含您要检查的数字),然后按 Ctrl + Shift + Enter 键在一起,您将得到结果,如果数字为质数,则单元格中将显示“ Prime”,否则,将显示“ Not Prime”,请参见屏幕截图:

doc检查素数1

2。 然后选择单元格C2,并将填充手柄向下拖动到要应用此公式的单元格上,所有的数字(如果不是素数)将被识别。 看截图:

doc检查素数2


箭头蓝色右气泡 使用用户定义的功能检查数字是否为质数

下列 用户定义功能 还可以帮助您检查数字是否为素数,请执行以下操作:

1。 按住 ALT + F11 键打开 Microsoft Visual Basic应用程序 窗口。

2。 点击 插页 > 模块,然后将以下代码粘贴到 模块窗口.

VBA代码:检查数字是否为质数:

Function CheckPrime(Numb As Single) As Boolean
'Updateby Extendoffice
    Dim X As Long
    If Numb < 2 Or (Numb <> 2 And Numb Mod 2 = 0) _
     Or Numb <> Int(Numb) Then Exit Function
    For X = 3 To Sqr(Numb) Step 2
        If Numb Mod X = 0 Then Exit Function
    Next
    CheckPrime = True
End Function

3。 然后保存并关闭此代码,返回到工作表,然后输入以下公式: = checkprime(A2) 放入数字列表旁边的空白单元格中,然后将填充手柄向下拖动到要包含此公式的单元格中,如果数字为质数,则显示TRUE,否则为FALSE,请参见屏幕截图:

doc检查素数3

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Comments (21)
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This comment was minimized by the moderator on the site
DO NOT ENTER THE FORMULAE IN THE CELL. Select the cell then paste the formulae in the formulae bar and press ctrl+shft+Enter. it should put { around the formulae} otherwise its wrong.
This comment was minimized by the moderator on the site
Craig, Thanks - that works! Sorry, I didn't read the instructions sufficiently carefully.
This comment was minimized by the moderator on the site
There is definitely a problem with this equation. I did a direct copy/paste and checked it was a faithful copy but it still has 9, 15, 21, 25, 33, 35 and 39 as primes when they obviously are not. On quick inspection it seems as if factors of 3 and 5 are giving rise to some sort of problem. It is a very complicated formula for a single cell - so much so, I can't work out what it is trying to do. I usually break such things down into multiple cells to make debugging easier (which, I believe is Excel best practice). The function seems to work, though.
This comment was minimized by the moderator on the site
There is definitely a problem with this equation. I did a direct copy/paste and checked it was a faithful copy but it still has 9, 15, 21, 25, 33, 35 and 39 as primes when they obviously are not. On quick inspection it seems as if factors of 3 and 5 are giving rise to some sort of problem. It is a very complicated formula for a single cell - so much so, I can't work out what it is trying to do. I usually break such things down into multiple cells to make debugging easier (which, I believe is Excel best practice).
This comment was minimized by the moderator on the site
Hi.

I am using an italian version of Excel, so the formula does not work and i have an error. Can you help me?

Thanks in advance
This comment was minimized by the moderator on the site
Hi, Gian,
If the formula does not work correctly for you, you can apply the second method-User Defined Function. Please try, hope it can help you!
Thank you!
This comment was minimized by the moderator on the site
Hi skyyang.
If it can be useful for others researchers, I inform you that I have found the solution to my problem here => http://www.riolab.org/index.php?option=com_content&view=article&id=172&Itemid=68

Thank you!
This comment was minimized by the moderator on the site
Yes it worked wen I did Ctrl+Shift+Enter... !! Thank you..:D and Do u mind explaining the algorithm please.
This comment was minimized by the moderator on the site
There's a reference error when you type in numbers that have more than 12 digits.
This comment was minimized by the moderator on the site
Hello,Nathan,
As you said, when the numbers are longer than 12 digits, it will become scientific notation. The formula is not applied for this formatting.
This comment was minimized by the moderator on the site
well 4095 is not a prime. still it gives result as prime no though. its incorrect.
This comment was minimized by the moderator on the site
Hello, vaibhav,
When you pasting above formula, you should press Ctrl + Shift + Enter keys together, not just Enter key, please try it again.
This comment was minimized by the moderator on the site
Your formula is not working. Eg. 1681 is NOT a prime but by formula it is.
=IF(A2=2,"Prime",IF(AND(MOD(A2,ROW(INDIRECT("2:"&ROUNDUP(SQRT(A2),0))))<>0),"Prime","Not Prime"))
This comment was minimized by the moderator on the site
Hello, Jan,
The above formula is correct, after pastingt the formula into a cell, you should press Ctrl + Shift + Enter keys together, not just Enter key.
Please try it again, thank you!
This comment was minimized by the moderator on the site
Yes, it was that case with CSE. Thanks (it's fixed now).
https://superuser.com/questions/674566/when-to-use-ctrlshiftenter-and-when-to-use-enter-in-excel

Btw Czech variant to:
=IF(A2=2,"Prime",IF(AND(MOD(A2,ROW(INDIRECT("2:"&ROUNDUP(SQRT(A2),0))))<>0),"Prime","Not Prime"))
is:
=KDYŽ(A2=2;"Prime";KDYŽ(A(MOD(A2;ŘÁDEK(NEPŘÍMÝ.ODKAZ("2:"&ROUNDUP(ODMOCNINA(A2);0))))<>0);"Prime";"Not Prime"))

Compare: https://imgur.com/a/4MgeV
This comment was minimized by the moderator on the site
this is my fastest version Sub generateprimenumbersbetween3() starting_number = 1 'input value here last_number = 30000 'input value here primenumbers = "" For a = starting_number To last_number c = a For b = 2 To c If a Mod b = 0 And c b Then Exit For Else If b = c Then primenumbers = primenumbers & " " & a Exit For Else If Round(a / (b + 1)) + 1 > b Then c = Round(a / (b + 1)) + 1 End If End If End If Next b Next a MsgBox primenumbers End Sub Sub ISPRIME3() number_to_be_checked = 2000000000 'input value here c = number_to_be_checked For b = 2 To c If number_to_be_checked Mod b = 0 And c b Then MsgBox "Not Prime. Divisible by " & b Exit Sub Else If b = c Then MsgBox "Prime" Exit Sub Else If Round(number_to_be_checked / (b + 1)) + 1 > b Then c = Round(number_to_be_checked / (b + 1)) + 1 End If End If End If Next b End Sub
This comment was minimized by the moderator on the site
The user defined function does not seem to work for numbers above ~16777213
This comment was minimized by the moderator on the site
Sub generateprimenumbersbetween() starting_number = 99990 'input value here last_number = 99999 'input value here primenumbers = "" For a = starting_number To last_number For b = 2 To a If a - b * Int(a / b) = 0 And a b Then Exit For Else If a = b Then primenumbers = primenumbers & " " & a End If End If Next b Next a MsgBox primenumbers End Sub Function primenumbersbetween(starting_number, last_number) primenumbers = "" For a = starting_number To last_number For b = 2 To a If a - b * Int(a / b) = 0 And a b Then Exit For Else If a = b Then primenumbers = primenumbers & " " & a End If End If Next b Next a primenumbersbetween = primenumbers End Function 'to check if a number is prime Sub ISPRIME() number_to_be_checked = 102 'input value here For b = 2 To number_to_be_checked If number_to_be_checked - b * Int(number_to_be_checked / b) = 0 And _ number_to_be_checked b Then MsgBox "Not Prime. Divisible by " & b Exit Sub Else If number_to_be_checked = b Then MsgBox "Prime" End If End If Next b End Sub 'to check if a number is prime Function ISPRIME2(number_to_be_checked) For b = 2 To number_to_be_checked If number_to_be_checked - b * Int(number_to_be_checked / b) = 0 And _ number_to_be_checked b Then ISPRIME2 = "Not Prime. Divisible by " & b Exit Function Else If number_to_be_checked = b Then ISPRIME2 = "Prime" End If End If Next b End Function
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