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如何在Excel中生成或列出所有可能的排列?

作者:晓阳 最后修改时间:2020-05-08

例如,我有三个字符XYZ,现在,我想基于这三个字符列出所有可能的排列,以获得六个不同的结果,例如:XYZ,XZY,YXZ,YZX,ZXY和ZYX。 在Excel中,如何根据不同的字符数快速生成或列出所有排列?

使用VBA代码根据字符生成或列出所有可能的排列


箭头蓝色右气泡 使用VBA代码根据字符生成或列出所有可能的排列

以下VBA代码可以帮助您根据字母的具体数量列出所有排列,请执行以下操作:

1。 按住 ALT + F11 键打开 Microsoft Visual Basic应用程序 窗口。

2。 点击 插页 > 模块,然后将以下代码粘贴到 模块 窗口。

VBA代码:列出excel中所有可能的排列

Sub GetString()
'Updateby Extendoffice
    Dim xStr As String
    Dim FRow As Long
    Dim xScreen As Boolean
    xScreen = Application.ScreenUpdating
    Application.ScreenUpdating = False
    xStr = Application.InputBox("Enter text to permute:", "Kutools for Excel", , , , , , 2)
    If Len(xStr) < 2 Then Exit Sub
    If Len(xStr) >= 8 Then
        MsgBox "Too many permutations!", vbInformation, "Kutools for Excel"
        Exit Sub
    Else
        ActiveSheet.Columns(1).Clear
        FRow = 1
        Call GetPermutation("", xStr, FRow)
    End If
    Application.ScreenUpdating = xScreen
End Sub
Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long)
    Dim i As Integer, xLen As Integer
    xLen = Len(Str2)
    If xLen < 2 Then
        Range("A" & xRow) = Str1 & Str2
        xRow = xRow + 1
    Else
        For i = 1 To xLen
            Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow)
        Next
    End If
End Sub

3。 然后按 F5 键以运行此代码,并弹出一个提示框,提醒您输入要列出所有排列的字符,请参见屏幕截图:

文档列表排列1

4。 输入字符后,再单击 OK 按钮,所有可能的排列都显示在活动工作表的A列中。 看截图:

文档列表排列2

备注:如果输入的字符长度等于或大于8个字符,则此代码将无效,因为排列过多。

文档列表排列3


列出或生成多列中的所有可能组合

如果您需要基于多列数据生成所有可能的组合,也许没有一种处理任务的好方法。 但, Kutools for Excel's 列出所有组合 实用程序可以帮助您快速轻松地列出所有可能的组合。 点击下载Kutools for Excel!

doc列出所有组合

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Comments (14)
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This comment was minimized by the moderator on the site
=LET(a,A2,i,LEN(a),IFERROR(TOROW(BYROW(MID(a,MID(BASE(SEQUENCE(i^i)-1,i,i),SEQUENCE(,i),1)+1,1),LAMBDA(A,
IFS(COUNTA(UNIQUE(A,1))=i,CONCAT(A)))),2),a))

i^i = PERMUTATIONA(i,i)
This comment was minimized by the moderator on the site
Olá !

Como faço para gerar pelo menos 10 permutações ?
This comment was minimized by the moderator on the site
Hello, Mateus,
To solve your problem, please apply the below code:(Note: if there are more than 8 characters, the code will execute slowly.)
Sub GetString()
'Updateby Extendoffice
    Dim xStr As String
    Dim FRow As Long
    Dim FC As Integer
    Dim xScreen As Boolean
    Dim xNumber As Long
    xNumber = 10 ' This is the max length of the characters you can change it to 11, 12, 13...as you need
    xScreen = Application.ScreenUpdating
    Application.ScreenUpdating = False
    xStr = Application.InputBox("Enter text to permute:", "Kutools for Excel", , , , , , 2)
    If Len(xStr) < 2 Then Exit Sub
    If Len(xStr) > xNumber Then
        MsgBox "Too many permutations!", vbInformation, "Kutools for Excel"
        Exit Sub
    Else
        ActiveSheet.Columns(1).Clear
        FRow = 1
        FC = 1
        Call GetPermutation("", xStr, FRow, FC)
    End If
    Application.ScreenUpdating = xScreen
End Sub
Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long, ByRef xc As Integer)
    Dim i As Integer, xLen As Integer
    xLen = Len(Str2)
    If xLen < 2 Then
        If xRow > 1000000 Then
            xc = xc + 1
            xRow = 1
        End If
       ActiveSheet.Cells(xRow, xc) = Str1 & Str2
        xRow = xRow + 1
    Else
        For i = 1 To xLen
            Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow, xc)
        Next
    End If
End Sub


Please have a try, hope it can help you!
This comment was minimized by the moderator on the site
Hi there, if the input string contains duplicate chars, then the sub produces duplicate permutations.
This does not happen if you make the following modification the the loop:

' ==========================
For i = 1 To xLen
If Instr( Left(Str2, i - 1), Mid(Str2, i, 1) ) = 0 then
Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow)
End if
Next
' ==========================

Creating temporary local variables for Mid(Str2, i, 1) and for Left(Str2, i - 1), and avoiding the test for i=1 makes it go faster:


' ==========================
Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long)
Dim i As Integer, xLen As Integer, Str2left as String, c as String
xLen = Len(Str2)
If xLen < 2 Then
Range("A" & xRow) = Str1 & Str2
xRow = xRow + 1
Else
Call GetPermutation(Str1 + Mid(Str2, 1, 1), Right(Str2, xLen - 1), xRow)
For i = 2 To xLen
c = Mid(Str2, i, 1)
Str2left = Left(Str2, i - 1)
If Instr( Str2left, c ) = 0 then
Call GetPermutation(Str1 + c, Str2left + Right(Str2, xLen - i), xRow)
End If
Next
End If
End Sub
' ==========================

Cheers,
DVdm
This comment was minimized by the moderator on the site
who can send me a list of 10 diferent items permutatted by 2 outcomes. this code doe

snt work on this
This comment was minimized by the moderator on the site
peki bunu listeleyecek bir program uygulama yok mu?basit sıradan bir hesaplamadan daha fazlasına ihtiyacı olan ne yapacak?
This comment was minimized by the moderator on the site
this code will not work because there are two many permutations


should be:

this code will not work because there are too many permutations


HTH
This comment was minimized by the moderator on the site
Hello, MC,
Thank you for your warm reminder, it is my mistake. I have corrected it.
Thanks a lot!
This comment was minimized by the moderator on the site
Hello everyone. I need help on this. I have two alphabets to be permutated in 20 rows. But am not getting it right. Anyone who could help me out should send the permutation to my email. .


1.a b b a
2.a a b b
3.a a b b
4.a a b b
5.a a b b
6.a a b b
7.a a b b
8.a a b b
9.a a b b
10.a a b b
11.a a b b
12.a a b b
13.a a b b
14.a a b b
15.a a b b
16.a a b b
17.a a b b
18.a a b b
19.a a b b
20.a a b b
This comment was minimized by the moderator on the site
How many sequences of 3things can be formed from 7 different things replacement and order is important?
This comment was minimized by the moderator on the site
3 to the power of 7: 2187
This comment was minimized by the moderator on the site
@Supraja...

in the first sub clear all cells... not just the first row
--Cells.Clear

Sub GetPermutation(Str1 As String, Str2 As String, ByRef xRow As Long)
Dim i As Integer, xLen As Integer
xLen = Len(Str2)
If xLen < 2 Then
'move to the next column when you get to 100
Cells(((xRow - 1) Mod 100) + 1, 1 + Int(xRow / 100)) = Str1 & Str2
xRow = xRow + 1
Else
For i = 1 To xLen
Call GetPermutation(Str1 + Mid(Str2, i, 1), Left(Str2, i - 1) + Right(Str2, xLen - i), xRow)
Next
End If
End Sub
This comment was minimized by the moderator on the site
Hello,

Im trying to get a permutation for 82 characters, the code provided works, but, since the columns are only 1048576, I want to move the next output in B,C,D..... Can any of you help me on this regard
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