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如何在Excel中的文本字符串中找到第一个/最后一个数字的位置?

添加一名作者 最后修改时间:2020-07-01

例如,您有一个由字母和数字组成的文本字符串列表。 如果要查找每个字符串中第一个或最后一个数字的位置,该怎么办? 实际上,使用公式可以帮助您快速找到指定文本字符串中第一个/最后一个数字的位置。 在本教程中,我们将向您显示处理此问题的详细信息。

在Excel中查找文本字符串中第一个数字的位置
在Excel中查找文本字符串中最后一个数字的位置


在Excel中查找文本字符串中第一个数字的位置

如下面的屏幕截图所示,要在文本字符串中查找第一个数字的位置,请执行以下操作。

1.选择单元格B2,将以下公式之一复制并粘贴到编辑栏中:

1)。 公式1: = MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A2&“ 0123456789”));

2)。 公式2: =MATCH(TRUE,ABS(CODE(MID(A2,ROW($A$1:INDEX(A:A,LEN(A2))),1))-52.5)<5,0) + 按Ctrl + 转移 + 输入;

3)。 公式3: =MIN(IF(ISERROR(FIND({1;2;3;4;5;6;7;8;9;0},A2)),"",FIND({1;2;3;4;5;6;7;8;9;0},A2))).

2.然后,第一个字符串的第一个数字位置显示在单元格B2中。 现在将“填充手柄”向下拖动到单元格B7,以填充以下范围。

然后列出整个字符串的所有第一个数字位置。


在Excel中查找文本字符串中最后一个数字的位置

找到第一个数字的位置之后,我们现在开始查找字符串中最后一个数字的位置。

在本节中,有两个公式可供您选择。

配方1: = MAX(IF(ISNUMBER(VALUE(MID(A2,ROW(INDIRECT(“ 1:”&LEN(A2))),1))),ROW(INDIRECT(“ 1:”&LEN(A2))))) ) + 按Ctrl + 转移 + 输入;

配方2: =MAX(IFERROR(FIND({1,2,3,4,5,6,7,8,9,0},A2,ROW(INDIRECT("1:"&LEN(A2)))),0)) + 按Ctrl + 转移 + 输入

1.选择单元格B2,将以上公式之一复制并粘贴到公式栏中,然后同时按Ctrl + Shift + Enter键。 然后,您可以看到结果显示在B2中。

2.选择B2,将“填充手柄”向下拖动到单元格B7,以自动填充范围。

然后,您将立即获得整个文本字符串的所有最后数字的位置。


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Comments (15)
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This comment was minimized by the moderator on the site
Ich habe gerade diese Lösung ausprobiert und es klappt bei mir nicht. Hat sich inzwischen etwas, was die Matrixformel betrifft, geändert?
This comment was minimized by the moderator on the site
Hi Wolfgang,

The formulas provided in this post work well in my case. What result did you get?
This comment was minimized by the moderator on the site
Thought I would let everyone know that I needed to find the last position of the house numbers in an address field in access. The only way I could do this was to export a short query to excel and run this formula. I know there is a way to get the excel functions in access but this was much easier. I had addresses that had varying house number lengths and then you throw in the 1st, 2nd, 3rd...St., Ave into the mix within the street name and you got a major problem parsing a very bad formatted address string.

address examples 1234 nw (or NW) 4th St.
12 West St North (or N)
123,456, and 789 Heritage Circle (or Crc)
123 & 456 N 1st. St

I figured out a way to parse off the first and second example real quick with some research (I would give credit, but right now I can't remember where I got the answer). It involved creating a VBA function to accomplish it. That worked great but I came to a problem when we come to the first "," or "and" or "&".

Using this formula in excel found the last number I needed without choosing the street number. Since most house numbers ended with a space " " between them and the direction segment or the street name segment, I added --- &" " after the find formula. Like this: in an array formula
=MAX(IFERROR(FIND({1,2,3,4,5,6,7,8,9,0}&" ",E2,ROW(INDIRECT("1:"&LEN(E2)))),0))
A quick export back to an access table and wala! you have the number.
202 & 206 N Blanche Ave = 9

Now I know I could probably parse the rest of the address in excel but it actually worked real well in Access, so I just decided to do the rest there.

If there is a way to do it all in Access, I couldn't find it or figure it out.
This comment was minimized by the moderator on the site
goood, thanks
This comment was minimized by the moderator on the site
That's what I needed =MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A2&"0123456789"));

thank you very much!
This comment was minimized by the moderator on the site
You are welcome O(∩_∩)O
This comment was minimized by the moderator on the site
how to get this to work in powerpivot
This comment was minimized by the moderator on the site
Hi,
Sorry can't help with this.
This comment was minimized by the moderator on the site
.... and here I thought that I knew Excel well. Bravo!!!!!
This comment was minimized by the moderator on the site
And here is a formula for finding the position of the last numeric character in a string, but WITHOUT using an array formula: =MAX(SEARCH(CHAR(9),SUBSTITUTE("0123456789"&A1,{0,1,2,3,4,5,6,7,8,9},CHAR(9),LEN(A1)+10-LEN(SUBSTITUTE("0123456789"&A1,{0,1,2,3,4,5,6,7,8,9},"")))))-10 The number 10 appearing in this formula, are due to the length of the constant string "0123456789", that is concatenated in this formula.
This comment was minimized by the moderator on the site
Many Thanks , Great
This comment was minimized by the moderator on the site
Hi George, your formula is may meet my requirement. I need similar formula to find out digit position in the string listed in "A" row in B row Required output 8 5 1 4 3 1 3 2 5 5 6 6 1 7 9 9 1 1 6 0 9 3 0 2 7 4 9 3 6 5 5 7 4 9 8 10 2 10 0 8 1 9
This comment was minimized by the moderator on the site
This was exactly what I wanted. Thank you.
This comment was minimized by the moderator on the site
The function 1). Formula 1: =MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A2&"0123456789")); It's absolutely what i needed and extremely cool! Thanks so much! Jon
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Hats off mate..
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